Answer:
PART I.
A.
SCENARIO A:
distance
scalar
has
has no
SCENARIO B:
displacement
vector
B.
10M/S
30MI/H
20CM/S
4km/h, east
35m/s, north
5mi/h, NE
C.
d=S x T,
t=D/S
d=v x t, (with arrow on top of vxt)
t=D/T
D.
0.5
0.75
1
1.25
E.
uniform
unequal
equal
accelerating
change
non-uniform
not accelerating
changes
F. I can say that some of his velocity is same to his speed.
PART II.
CHANGE IN VELOCITY
0.25
CHANGE IN TIME
1.5
2.5
3.5
ACCELERATION
Explanation:
I answer all the questions and I hope it helps y'all :D
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Answers & Comments
Answer:
PART I.
A.
SCENARIO A:
distance
scalar
has
has no
distance
SCENARIO B:
displacement
vector
has
has
displacement
B.
SCENARIO A:
10M/S
30MI/H
20CM/S
SCENARIO B:
4km/h, east
35m/s, north
5mi/h, NE
C.
SCENARIO A:
d=S x T,
t=D/S
SCENARIO B:
d=v x t, (with arrow on top of vxt)
t=D/T
D.
SCENARIO A:
0.5
0.5
0.5
0.5
SCENARIO B:
0.5
0.75
1
1.25
E.
SCENARIO A:
uniform
unequal
equal
accelerating
change
SCENARIO B:
non-uniform
unequal
equal
not accelerating
changes
F. I can say that some of his velocity is same to his speed.
PART II.
CHANGE IN VELOCITY
0.25
0.25
0.25
CHANGE IN TIME
1.5
2.5
3.5
ACCELERATION
0.5
0.5
0.5
Explanation:
I answer all the questions and I hope it helps y'all :D