chasinghaze1217
Hello po user's, Pwede pa-rate at pa-heart ng mga Answers ko sa Math? wag mopong kalimutan e-rate ang mga Answers kopo sa Math, sana po mabait pong basahin ang aking message.
chasinghaze1217
Hello po user's, Pwede pa-rate at pa-heart ng mga Answers ko sa Math? wag mopong kalimutan e-rate ang mga Answers kopo sa Math, sana po mabait pong basahin ang aking message.
Answers & Comments
Answer:
I lang po 'yan hehe Sana makatulong
I.
1
2.
3.
II.
1.![\purple{\boxed{50 {x}^{5} {y}^{7}}} \purple{\boxed{50 {x}^{5} {y}^{7}}}](https://tex.z-dn.net/?f=%5Cpurple%7B%5Cboxed%7B50%20%7Bx%7D%5E%7B5%7D%20%20%7By%7D%5E%7B7%7D%7D%7D%20)
2.![\green{\boxed{{(x - 8})^{2} (x + 8)}} \green{\boxed{{(x - 8})^{2} (x + 8)}}](https://tex.z-dn.net/?f=%5Cgreen%7B%5Cboxed%7B%7B%28x%20-%208%7D%29%5E%7B2%7D%20%28x%20%2B%208%29%7D%7D)
III.
1.![\frac{ {x}^{2} + 4x - 5}{ {x}^{2} - 2x - 3} - \frac{2}{x + 1} = \frac{2(x - 1)}{(x - 3)(x - 1)} =\orange{\boxed{ \frac{2}{x - 3}}} \frac{ {x}^{2} + 4x - 5}{ {x}^{2} - 2x - 3} - \frac{2}{x + 1} = \frac{2(x - 1)}{(x - 3)(x - 1)} =\orange{\boxed{ \frac{2}{x - 3}}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%204x%20-%205%7D%7B%20%7Bx%7D%5E%7B2%7D%20%20-%202x%20-%203%7D%20%20-%20%20%5Cfrac%7B2%7D%7Bx%20%2B%201%7D%20%20%3D%20%20%20%5Cfrac%7B2%28x%20-%201%29%7D%7B%28x%20-%203%29%28x%20-%201%29%7D%20%20%3D%5Corange%7B%5Cboxed%7B%20%5Cfrac%7B2%7D%7Bx%20-%203%7D%7D%7D%20)
2.![\frac{m + 1}{ {m}^{2} - 25 } + \frac{2m}{m - 5} = {\boxed{ \frac{2 {m}^{2} + 11m + 1}{ {m}^{2} - 25 }}} \frac{m + 1}{ {m}^{2} - 25 } + \frac{2m}{m - 5} = {\boxed{ \frac{2 {m}^{2} + 11m + 1}{ {m}^{2} - 25 }}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bm%20%2B%201%7D%7B%20%7Bm%7D%5E%7B2%7D%20-%2025%20%7D%20%20%2B%20%20%5Cfrac%7B2m%7D%7Bm%20-%205%7D%20%20%3D%20%7B%5Cboxed%7B%20%5Cfrac%7B2%20%7Bm%7D%5E%7B2%7D%20%20%2B%2011m%20%2B%201%7D%7B%20%7Bm%7D%5E%7B2%7D%20-%2025%20%7D%7D%7D%20)