[tex]\huge \boxed{\mathbb{MY\ANSWER}\downarrow}[/tex]

Expand the square

(2−4)2

\left(2u-4v\right)^{2}

(2−4)(2−4)

(2−4)(2−4)

{\color{#c92786}{(2u-4v)(2u-4v)}}

2(2−4)−4(2−4)

2(2−4)−4(2−4)

{\color{#c92786}{2u(2u-4v)}}-4v(2u-4v)

42−8−4(2−4)

42−8−4(2−4)

4u^{2}-8uv{\color{#c92786}{-4v(2u-4v)}}

42−8−8+162

42−8−8+162

4u^{2}{\color{#c92786}{-8uv}}{\color{#c92786}{-8uv}}+16v^{2}

42−16+162

Answer:C.