Answer: 1. multiply by 2 2. in first term multiply it in second term, example: 1 x 1/2 = 1/2 1/2 x 1/2 = 1/4 1/4 x 1/4 = 1/8, and so on, ( you try it till 8)
3. i think you just have to multiply it by 10, till you reach till 10th term
4. the sequence 3, 9, 27, 81, . . . This is a geometric sequence since there is a common ratio between each of them.
In this case, multiplying the previous term in the sequence by 3 gives the next term.
An = a1 rn - 1.
Where, r = 3, a1 = 3.
Form of geometric sequence = a1 rn - 1.
Substituting , we get,
a5 = 3(3)5 - 1
= 3(3)4
= 3(81)
= 243
a6 = 3 (3)6 - 1
= 3(3)5
= 3(243)
= 729
a7 = 3 (3)7 - 1 = 3(3)6
= 3(729)
= 2187
Therefore, the next three terms are 243, 729 and 2187.
5. First you must find r, the common ratio.
You find this with the following formula: r = tsub2/tsub1 r = #(-1/2)/1)
r = −1/2
The ratio is therefore
−1/2 The formula for the sum of an infinite geometric series is
Answers & Comments
Answer:
1. multiply by 2
2. in first term multiply it in second term,
example: 1 x 1/2 = 1/2
1/2 x 1/2 = 1/4
1/4 x 1/4 = 1/8, and so on, ( you try it till 8)
3. i think you just have to multiply it by 10, till you reach till 10th term
4. the sequence 3, 9, 27, 81, . . . This is a geometric sequence since there is a common ratio between each of them.
In this case, multiplying the previous term in the sequence by 3 gives the next term.
An = a1 rn - 1.
Where, r = 3, a1 = 3.
Form of geometric sequence = a1 rn - 1.
Substituting , we get,
a5 = 3(3)5 - 1
= 3(3)4
= 3(81)
= 243
a6 = 3 (3)6 - 1
= 3(3)5
= 3(243)
= 729
a7 = 3 (3)7 - 1
= 3(3)6
= 3(729)
= 2187
Therefore, the next three terms are 243, 729 and 2187.
5. First you must find r, the common ratio.
You find this with the following formula: r = tsub2/tsub1
r = #(-1/2)/1)
r = −1/2
The ratio is therefore
−1/2 The formula for the sum of an infinite geometric series is
s∞= a/1−r
s∞= 1/ (1 divide by 1- (-1/2)
1−(−1/2)
s∞= 1/ 3/2
s∞= 2/3
(hope it helps)