Answer:
C po sagot this is right po
Step-by-step explanation:
hope it helps
[tex]\large{{\mathcal{⋆MATHEMATICS⋆}}}[/tex]
What is the area of the shaded region.
[tex]\boxed{{\large{{\sf{{Area \: of \: outer \: shape = area \: of \: square}}}}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = (side) {}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = (10cm) {}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 100cm {}^{2} {}^{} }}}}[/tex]
[tex]\boxed{{\large{{\sf{{Area \: of \: inner \: shape = area \: of \: circle}}}}}} [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = \pi {r}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( \frac{diameter}{2} )}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( \frac{10cm}{2} )}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( 5cm )}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( 25cm )}^{} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 78.5 {cm}^{2} }}}}[/tex]
[tex]\boxed{{\large{{\sf{{Area \: of \: shaded \: region}}}}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea_{square} -\tt{A}\sf{rea_{cirle} }}}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\sf{100cm { }^{2} - 78.5cm {}^{2} = \boxed{\sf{\green{21.5cm {}^{2} } }}}}}[/tex]
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《JichuSooya07⚘》
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Answers & Comments
Answer:
C po sagot this is right po
Step-by-step explanation:
hope it helps
Verified answer
[tex]\large{{\mathcal{⋆MATHEMATICS⋆}}}[/tex]
What is the area of the shaded region.
[tex]\boxed{{\large{{\sf{{Area \: of \: outer \: shape = area \: of \: square}}}}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = (side) {}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = (10cm) {}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 100cm {}^{2} {}^{} }}}}[/tex]
[tex]\boxed{{\large{{\sf{{Area \: of \: inner \: shape = area \: of \: circle}}}}}} [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = \pi {r}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( \frac{diameter}{2} )}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( \frac{10cm}{2} )}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( 5cm )}^{2} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 3.14 {( 25cm )}^{} }}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea = 78.5 {cm}^{2} }}}}[/tex]
[tex]\boxed{{\large{{\sf{{Area \: of \: shaded \: region}}}}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\tt{A\sf{rea_{square} -\tt{A}\sf{rea_{cirle} }}}}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \large{{\sf{100cm { }^{2} - 78.5cm {}^{2} = \boxed{\sf{\green{21.5cm {}^{2} } }}}}}[/tex]
================================================
Have a nice day ૮ ˶ᵔ ᵕ ᵔ˶ ა
《JichuSooya07⚘》