Answer:
1st child: ₱100
2nd child: ₱200
3rd child: ₱250
Step-by-step explanation:
Let x be the value of the amount distributed to the three children
₱550 = 2x+4x+5x
₱550 = 11x
₱50 = x
1st child: 2x
2x = 2(₱50)
= ₱100
2nd child: 4x
4x = 4(₱50)
= ₱200
3rd child: 5x
5x = 5(₱50)
= ₱250
checking:
2x + 4x + 5x = ₱550
2(₱50) + 4(₱50) + 5(₱50) = ₱550
₱100 + ₱ 200 + ₱250 = ₱550
₱550 = ₱550
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Answers & Comments
Answer:
1st child: ₱100
2nd child: ₱200
3rd child: ₱250
Step-by-step explanation:
Let x be the value of the amount distributed to the three children
₱550 = 2x+4x+5x
₱550 = 11x
₱50 = x
1st child: 2x
2x = 2(₱50)
= ₱100
2nd child: 4x
4x = 4(₱50)
= ₱200
3rd child: 5x
5x = 5(₱50)
= ₱250
checking:
2x + 4x + 5x = ₱550
2(₱50) + 4(₱50) + 5(₱50) = ₱550
₱100 + ₱ 200 + ₱250 = ₱550
₱550 = ₱550