Answer:
Solution
∠EFD=60
∘
=∠LEB(correspondingangle)
∵AB∥CD[onstraightlineangleis180
]
⇒∴∠LEB+∠BEP+∠PEF=180
⇒60
+40
+∠PEF=180
⇒
∠PEF=180
−100=80
[∵∠EFD=∠EFP+∠PFD]
⇒y+25=60
[∵sumofallanglesoftriangleis180
⇒y=60−25
y=35
Ans.
ThentheΔFEP
⇒80
+x+25
=180
⇒x+105=180
⇒x=180
−105
x=75
what's the joke
Step-by-step explanation:
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Answers & Comments
Verified answer
Answer:
Solution
∠EFD=60
∘
=∠LEB(correspondingangle)
∵AB∥CD[onstraightlineangleis180
∘
]
⇒∴∠LEB+∠BEP+∠PEF=180
∘
⇒60
∘
+40
∘
+∠PEF=180
∘
⇒
∠PEF=180
∘
−100=80
∘
[∵∠EFD=∠EFP+∠PFD]
⇒y+25=60
∘
[∵sumofallanglesoftriangleis180
∘
]
⇒y=60−25
y=35
∘
Ans.
ThentheΔFEP
⇒80
∘
+x+25
∘
=180
∘
⇒x+105=180
∘
⇒x=180
∘
−105
x=75
∘
Ans.
Answer:
what's the joke
Step-by-step explanation: