Step-by-step explanation:
Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son =x+5
= 5+5
= 10years
and the present age of father=7x+5
=35+5
=40years
Hope it helps...
Answer:∴7x+10=3(x+10)
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Step-by-step explanation:
Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son =x+5
= 5+5
= 10years
and the present age of father=7x+5
=35+5
=40years
Hope it helps...
Answer:∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son =x+5
= 5+5
= 10years
and the present age of father=7x+5
=35+5
=40years
Hope it helps...
Step-by-step explanation: