So, Let Pipe A Fill in 4 hrs and Pipe b fill in 5 hrs. Pipe A Fills the whole Volume in 4 hrs. So Pipe A Can Fill 1/4 of the total Volume in An Hour. Similarly,Pipe B Can Fill 1/5 Of The Total Volume. So In 2 Hour Both Of The Pipes Together Fill 1/4 +1/5 of the total Volume. 2hr = 9 /20. of the volume So Total hours would Be 40/9 That is 4.44 Hrs. This Is The The Solution To The Given Question.
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ajayearl077p35udj
how can u say that both of them work for twoo hours its only one hour please check it
Answers & Comments
Given that work was done by x in an hour = 1/4.
Given that work was done by y in an hour = 1/5.
If x and y work alternately, then the work done by them in 2 hours
= (1/4 + 1/5)
= 9/20.
Then the work was done by them in 4 hours if they work alternately
= 2(9/20)
= 18/20
= 9/10.
Then the Remaining part = 1 - 9/10
= 1/10.
Now,
1/10th part of the tank is filled by x in (1/10) * 4
= 4/10
= 2/5 hours
= 0.4 hours
= 24 minutes.
Therefore, the total time is taken to fill the tank = 4 hours 24 minutes.
Hope this helps!
Verified answer
So, Let Pipe A Fill in 4 hrs and Pipe b fill in 5 hrs.Pipe A Fills the whole Volume in 4 hrs.
So Pipe A Can Fill 1/4 of the total Volume in An Hour.
Similarly,Pipe B Can Fill 1/5 Of The Total Volume.
So In 2 Hour Both Of The Pipes Together Fill 1/4 +1/5 of the total Volume.
2hr = 9 /20. of the volume
So Total hours would Be 40/9
That is 4.44 Hrs.
This Is The The Solution To The Given Question.