Answer:
Let's call the two numbers x and y.
According to the problem statement, one of the numbers is four times the other, so we can write:
x = 4y (equation 1)
We are also told that the sum of the numbers is 35, so we can write:
x + y = 35 (equation 2)
Now we can substitute equation 1 into equation 2 to eliminate x and get an equation in terms of y:
4y + y = 35
5y = 35
y = 7
Now that we know y, we can use equation 1 to find x:
x = 4y = 4(7) = 28
7 and 28
Step-by-step explanation:
let the no. be x
ATQ:
x+4x = 35
5x = 35
x = 7
Another no.= 4x= 28
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Verified answer
Answer:
Let's call the two numbers x and y.
According to the problem statement, one of the numbers is four times the other, so we can write:
x = 4y (equation 1)
We are also told that the sum of the numbers is 35, so we can write:
x + y = 35 (equation 2)
Now we can substitute equation 1 into equation 2 to eliminate x and get an equation in terms of y:
4y + y = 35
5y = 35
y = 7
Now that we know y, we can use equation 1 to find x:
x = 4y = 4(7) = 28
Therefore, the two numbers are 7 and 28.
Answer:
7 and 28
Step-by-step explanation:
let the no. be x
ATQ:
x+4x = 35
5x = 35
x = 7
Another no.= 4x= 28