On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO2. What is the percentage of Carbon in the compound?
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mass of organic compound --- 0.246 gmass of CO2 formed ----- 0.198 g
percentage of Carbon = 12 x mass of CO2 formed x 100
44 mass of organic compound
percentage of carbon = 12 /44 x 0.198/0.246 x 100
percentage of carbon = 2.376/10.824 x 100
% carbon = 0.2195 x 100
%carbon = 21.95
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21.95% of carbon is present in the compound
Explanation:
In the given question
mass of organic compound=0.246 g
mass of carbon dioxide= 0.198 g
mass of water= 0.1014 g
mass of water=0.1014 g
% of carbon:
12/44*0.198/0.246*100
=21.95%
% of Hydrogen
2/18*MASS OF H2O /MASS OF COMPOUND*100
=2/18*0.1014/0.246*100
4.58%