Answer:
There were (A) 1200 more chickens than cows at first.
Step-by-step explanation:
Given:
To Find:How many chickens than cows were there at first.
Calculation:
Let, the common ratio is = y
Number of chickens = 5y
Number of cows = 3y
After selling 300 chickens number of chickens = 5y - 300
Now the ratio of chickens and cows are = 5y-300 : 3y
5y-300:3y = 3:2
We can write this like below,
5y-300 / 3y = 3/2
or, 2(5y - 300) = 3(3y)
or, 10y - 600 = 9y
or, 10y - 9y = 600
or, y = 600
Number of chickens were there at first = 5(600) = 3000
Number of cows were there at first = 3(600) = 1800
Number of chickens greater than cows = 3000 - 1800 = 1200
Option (A) 1200 is the correct answer.
Hence, There were (A) 1200 more chickens than cows at first. ( ans. )
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Answers & Comments
Answer:
There were (A) 1200 more chickens than cows at first.
Step-by-step explanation:
Given:
To Find:
How many chickens than cows were there at first.
Calculation:
Let, the common ratio is = y
Number of chickens = 5y
Number of cows = 3y
After selling 300 chickens number of chickens = 5y - 300
Now the ratio of chickens and cows are = 5y-300 : 3y
5y-300:3y = 3:2
We can write this like below,
5y-300 / 3y = 3/2
or, 2(5y - 300) = 3(3y)
or, 10y - 600 = 9y
or, 10y - 9y = 600
or, y = 600
Number of chickens were there at first = 5(600) = 3000
Number of cows were there at first = 3(600) = 1800
Number of chickens greater than cows = 3000 - 1800 = 1200
Option (A) 1200 is the correct answer.
Hence, There were (A) 1200 more chickens than cows at first. ( ans. )