Observe the 2NH₂(g) + 3CuO(s)→→ N₂(g) + 3Cu(s) + 3H₂O(l)
(a) Which substance is reducing agent in above reaction?
(b) Which substance is getting reduced to what? What will be change in colour?
(c) Give an example of an oxidation reaction which is also a combustion reaction.
(d) Give the reaction of reduction of CuO by hydrogen gas.
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Answers & Comments
Explanation:
3CuO+2NH
3
⟶N
2
+3H
2
O+3Cu
Oxidation state of N in NH
3
=−3
Oxidation state of N in N
2
=0
The change in oxidation state of N is loss of 3 electrons.
There are two atoms of nitrogen, hence the change involves loss of 6e
−
for 1 mol of N
2
.
3CuO+2NH3⟶N2+3H2O+3Cu
Oxidation state of N in NH3=−3
Oxidation state of N in N2=0
The change in oxidation state of N is loss of 3 electrons.
There are two atoms of nitrogen, hence the change involves loss of 6e− for 1 mol of N2.
Video Explanation
3CuO+2NH3⟶N2+3H2O+3Cu
Oxidation state of N in NH3=−3
Oxidation state of N in N2=0
The change in oxidation state of N is loss of 3 electrons.
There are two atoms of nitrogen, hence the change involves loss of 6e− for 1 mol of N2.