Answer:
Reaction of oxalate ions being oxidized by MnO4− ions is:
MnO4−+C2O42−⇌Mn+2+2CO2
+7 +3 +2 +4
MnO4−→Mn+2 [Decrease 5]
C2O4→2CO2 [Increase 1] (1×2=2 increase)
Final Reaction: 2MnO4−+5C2O42−⇌2Mn+2+10CO2
Therefore, since 2 moles of MnO4− oxidize 5 moles of C2O42−
So, 1 mole of MnO4− will oxidize 25 moles of C2O42−
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
Reaction of oxalate ions being oxidized by MnO4− ions is:
MnO4−+C2O42−⇌Mn+2+2CO2
+7 +3 +2 +4
MnO4−→Mn+2 [Decrease 5]
C2O4→2CO2 [Increase 1] (1×2=2 increase)
Final Reaction: 2MnO4−+5C2O42−⇌2Mn+2+10CO2
Therefore, since 2 moles of MnO4− oxidize 5 moles of C2O42−
So, 1 mole of MnO4− will oxidize 25 moles of C2O42−