Answer:

4 moles

Explanation:

2Al + 3Cl2 -------> 2AlCl3

• 3 mole Cl2 require 2 mole Al
• 1 mole Cl2 will require => (2/3)mole of Al
• 6 mole Cl2 will require => (2/3)×6 = 4 mole of Al

=> Cl2 is limiting reactant

• 3 mole Cl2 form 2mole AlCl3
• 1 mole Cl2 will form => (2/3) mole AlCl3
• 6 mole Cl2 will form => (2/3)×6 = 4moes of AlCl3