Answer:

2.) 2m^2+5m-3

3.) 3c^2-51

4.) 2x^3-9x^2-x+2

Step-by-step explanation:

2.)

(m+3)(2m-1)

= m(2m)-m+3(2m)-3

= 2m^2 - m+3×2m-3

= 2m^2 - m+6m-3

= 2m^2 + 5m -3

3.)

(6-3)(c^2-20+3)

= 6(c^2-20+3)-3(c^2-20+3)

= 6c^2-120+18-3c^2+60-9

= 3c^2-120+18+60-9

= 3c^2-51

4.)

( 2x+1)(x^2-5x+2)

= 2x(x^2-5x+2)+1(x^2-5x+2)

= 2x^3 -10x^2+4x+1(x^2-5x+2)

= 2x^3 -10x^2+4x+x^2-5x+2

= 2x^3 -9x^2+4x-5x+2

= 2x^3-9x^2-x+2

naduduling ako pakicheck nalang if may mali :P

Answer:

sorry po hindi ko po masasabi ang answer

Step-by-step explanation:

(m+3) (2m-1)

ang basa po dito ay

a number plus three times two times a number minos one

yung m po ay a number pero po kapag ganito (2m+1)

ay two times a number plus one na po

hope it helps kung hindi nyo po maintindihan basahin nyo nalang po sa module

thanks