Answer:
hope it's help
Step-by-step explanation:
1. h (x)- |7x-8| = -1
then h(x) = |7x-8| -1
For any given x, there is only one value of h(x).
So this is an absolute value function
2. -22 + |x-π| = |y|
For some x, there are two values of y.
for example, x= π+23|y|= 1y=1 or y= -1, so this is not an absolute value function.
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Answers & Comments
Answer:
hope it's help
Step-by-step explanation:
1. h (x)- |7x-8| = -1
then h(x) = |7x-8| -1
For any given x, there is only one value of h(x).
So this is an absolute value function
2. -22 + |x-π| = |y|
For some x, there are two values of y.
for example, x= π+23|y|= 1y=1 or y= -1, so this is not an absolute value function.