A. Find the measure of the required part of AABC. (with solution)
1. Given B = 130°, a = 4, and c = 7, solve for side b.
2. Given A = 50°, b = 41, and c = 30, solve for side a.
3. Given a = 5, b = 7, and c = 11, solve for angle A.
4. Given a = 3, b = 4, c = 6, solve for angle B.
5. Given a = 286, b = 310, and c = 444, solve for angle C.
→ correct/complete answer= mark as brainlíest
→ wrong/nonsense answer=
R E P O R T
1. Given B = 130°, a = 4, and c = 7, solve for side b.
2. Given A = 50°, b = 41, and c = 30, solve for side a.
3. Given a = 5, b = 7, and c = 11, solve for angle A.
4. Given a = 3, b = 4, c = 6, solve for angle B.
5. Given a = 286, b = 310, and c = 444, solve for angle C.
→ correct/complete answer= mark as brainlíest
→ wrong/nonsense answer=
R E P O R T
Add an Answer
More Questions From This User See All
Answers & Comments
Verified answer
Answer:
1. side b = 10.05
2. side a = 31.62
3. angle A = 19.69°
4. angle B = 36.34°
5. angle C = 96.23°
Step-by-step explanation:
b = √(a² + c² - 2ac • cos(B))
b = √(4² + 7² - 2 (4)(7) • cos(130°)
b = 10.049682
b = 10.05
a = √(b² + c² - 2bc • cos(A)
a = √(41² + 30² - 2(41)(30) • cos(50°)
a = 31.6187
a = 31.62
∠A = arccos((b² + c² - a²) / 2bc)
∠A = arccos ((7² + 11² - 5²) / 2(7)(11))
∠A = 19.69°
∠B = arccos((a² + c² - b²)/ 2ac)
∠B = arccos((3² + 6² - 4²)/ 2(3)(6))
∠B = 36.34°
∠C = arccos((a² + b² - c²)/ 2ab)
∠C = arccos((286² + 310² - 444²)/ 2(286)(310))
∠C = 96.23°