Need help Use the frequency distribution below. complete the table and calculate 1.D 2.Q. 3. Pro Class Interval frequency Lower Boundaries (LB) Less than Cumulative Frequency (sed) 5. 3 10 7 4 100-109 90-99 80-89 70-79 60-69 50-59 40-49 30-39 20-29 10-19 6 8 4 1 2
Answers & Comments
Answer:
LB
NUMBER OF HOURS SUBTRACT TO 0.5
100-0.5= 99.5
90-0.5 = 89.5
<CF
LAST NUMBER OF FREQUENCY COPY AND WRITE INTO LAST NUM. OF <CF
2+1 = 3
3+4= 7
7+8= 15
and so on...
Step-by-step explanation:
hope its helps :)