(G-Given, F-Find, F-Formula, S-Solution, and F - Final answer )
1. What is the Percent by volume of a solution formed by adding 15 L of acetone to 28 L of water?
Given:
The volume of Solute = 28 L
The Volume of Solution = 15 L
Find:
Percent by Volume
Solution:
Percent by Volume =[tex]\sf{{\frac{Volume \: of \: Solute }{Volume \: of \: Solution} \times 100}}[/tex]
Percent by Volume = [tex]\sf{\frac{28L}{15L} \times 100}}[/tex]
Percent by Volume = [tex]\sf{{1.9 \times 100}}[/tex]
Percent by Volume = 190%
Final Answer:
Therefore, the Percent by Volume in the given problem is 190%.
2. An experiment requires a solution that is 80% methyl alcohol by volume. What volume of methyl alcohol should be added to 200 mL of water to make this solution?
Given:
The volume of Solute = 28 L
The Volume of Solution =?
Find:
The volume of the methyl alcohol
Solution:
The volume of the methyl alcohol = x
Volume of water = y = 200 mL
The volume of Solution = x + y
Volume of Solution = 80%
The volume of the methyl alcohol = [tex]\sf{{ \frac{x}{x+y} \times 100}}[/tex]
The volume of the methyl alcohol = [tex]\sf{{ \frac{x}{x + 200mL} \times 100}}[/tex]
The volume of the methyl alcohol = [tex]\sf{{800mL}}[/tex]
Final Answer:
Therefore, the volume of the methyl alcohol in the given problem is 800mL.
Answers & Comments
Directions: Solve the following problems.
(G-Given, F-Find, F-Formula, S-Solution, and F - Final answer )
1. What is the Percent by volume of a solution formed by adding 15 L of acetone to 28 L of water?
Given:
Find:
Solution:
Final Answer:
2. An experiment requires a solution that is 80% methyl alcohol by volume. What volume of methyl alcohol should be added to 200 mL of water to make this solution?
Given:
Find:
Solution:
The volume of the methyl alcohol = [tex]\sf{{ \frac{x}{x+y} \times 100}}[/tex]
The volume of the methyl alcohol = [tex]\sf{{ \frac{x}{x + 200mL} \times 100}}[/tex]
The volume of the methyl alcohol = [tex]\sf{{800mL}}[/tex]
Final Answer:
Good Luck!