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[tex] \color{aqua} \tt{Given: Side \: OF \: Equilateral \: Triangle = \: 12 \sqrt{3} {cm}^{2}}[/tex]
[tex] \color{aqua} \tt{To \: find: \: Area}[/tex]
[tex] \color{aqua} \tt{Solution: Area = \sqrt{ \frac{3}{4} {a}^{2}}}[/tex]
[tex] \color{aqua} \tt{ = \sqrt{ \frac{3}{4}(12 \sqrt{12)^{2} }}}[/tex]
[tex] \huge\colorbox{black}{\boxed{\colorbox{pink}{\color{black}{⊱TOTAL ANSWER:{}}}}}[/tex]
[tex] \red{\overbrace{\underbrace{\tt\blue{\:\:\:\:\:\:\:\:\:MissUmaruChan ⚘\:\:\:\:\:\:\:}}}}[/tex]
[tex] \tt \color{pink}{CarryOnLearning⚘}[/tex]
[tex] \sf\color{aqua}{⊱MATH \: PROBLEM \: SOLVE!!}[/tex]
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[tex] \huge\colorbox{black}{\boxed{\colorbox{pink}{\color{black}{⊱ANSWER:{}}}}}[/tex]
[tex]\red{⊱┈──────────────────────────┈⊰}[/tex]
[tex] \huge\colorbox{black}{\boxed{\colorbox{pink}{\color{black}{⊱EXPLAINED/SOLUTION:{}}}}}[/tex]
[tex] \color{aqua} \tt{Given: Side \: OF \: Equilateral \: Triangle = \: 12 \sqrt{3} {cm}^{2}}[/tex]
[tex] \color{aqua} \tt{To \: find: \: Area}[/tex]
[tex] \color{aqua} \tt{Solution: Area = \sqrt{ \frac{3}{4} {a}^{2}}}[/tex]
[tex] \color{aqua} \tt{ = \sqrt{ \frac{3}{4}(12 \sqrt{12)^{2} }}}[/tex]
[tex]\red{⊱┈──────────────────────────┈⊰}[/tex]
[tex] \huge\colorbox{black}{\boxed{\colorbox{pink}{\color{black}{⊱TOTAL ANSWER:{}}}}}[/tex]
[tex] \red{\overbrace{\underbrace{\tt\blue{\:\:\:\:\:\:\:\:\:MissUmaruChan ⚘\:\:\:\:\:\:\:}}}}[/tex]
[tex]\red{⊱┈──────────────────────────┈⊰}[/tex]
[tex] \tt \color{pink}{CarryOnLearning⚘}[/tex]
[tex] \sf\color{aqua}{⊱MATH \: PROBLEM \: SOLVE!!}[/tex]