NCERT BRAINLIEST QUESTION
How can three resistors of resistance 2 ohms , 3 ohms and 6 ohms be connected to give a total resistance of (a) 4 ohms and (b) one ohms?
How can three resistors of resistance 2 ohms , 3 ohms and 6 ohms be connected to give a total resistance of (a) 4 ohms and (b) one ohms?
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Then the net R from parallel connection is connected in series with the remaining 2 Q resistor to get a total resistance of 4 Q. This is because in series combination:
R=R1+ R2
R=2 + 2
R=4Ω
The arrangement of three resistors of 2,3Ω and 6Ω which gives a total resistance of 4Ω can now be represented as follows:
Thus, we can obtain a total resistance of 4Ω by connecting parallel combination of 3Ω and 6Ω resistors in series with 2Ω resistor.
(b) In order to obtain a total resistance of 1Ω from three resistors of 2Ω, 3Ω and 6Q, all the three resistors should be connected in parallel. This is because in parallel combination:
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