Answer:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=6

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=6

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=6

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=0

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=6

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=6

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=6

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=63x3=6ed)(3)

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=63x3=6ed)(3)x=2 or (2,0)

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=63x3=6ed)(3)x=2 or (2,0)We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=63x3=6ed)(3)x=2 or (2,0)We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.graph{(x^2+(y-3)^2-0.125)((x-2)^2+ y^2-0.125)(3x+2y-6)=0 [-20, 20, -10, 10]}

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=63x3=6ed)(3)x=2 or (2,0)We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.graph{(x^2+(y-3)^2-0.125)((x-2)^2+ y^2-0.125)(3x+2y-6)=0 [-20, 20, -10, 10]}Now, we can shade the left side of the line. And we need to make the boundary line a dashed line because the inequality operator does not contain an "or equal to" clause.

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.For: x=0(3⋅0)+2y=60+2y=62y=62y2=62y=3 or (0,3)For: y=03x+(2⋅0)=63x+0=63x=63x3=6ed)(3)x=2 or (2,0)We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.graph{(x^2+(y-3)^2-0.125)((x-2)^2+ y^2-0.125)(3x+2y-6)=0 [-20, 20, -10, 10]}Now, we can shade the left side of the line. And we need to make the boundary line a dashed line because the inequality operator does not contain an "or equal to" clause.graph{(3x+2y-6) < 0 [-20, 20, -10, 10]}