Answer:

These problems are example of conservation of momentum.It states that the sum of initial momenta is equal to the sum of final momentamThe formula is:

M1V1+M2V1=M1V2+M2V2

But in these problems,they produce a type of collision called inelastic collision.Inelastic collision occurs when two bodies collide,and after that,they now move together with a common velocity.The formula for inelastic collision is:

M1V1+M2V1=(M1+M2)V2

1.

Before we solve anything,let us first enumerate what we know:

Before Collision:

M1=0.15 kg

V1=1.5 m/s

M2=0.10 kg

V1=0 m/s(at rest)

Let us now use the inelastic collision formula to find their velocity after they stick together.

M1V1+M2V1=(M1+M2)V2

Substituting and solving for V2:

(0.15)(1.5)+(0.10)(0)=(0.15+0.10)V2

0.225+0=(0.25)V2

0.225=(0.25)V2

V2=0.9 m/s

Therefore,after the collision,they now move together at 0.9 m/s.

2.

Again,before solving,we need to analyze our problem and list what we know:

M1=1.5 kg

V1=1.8 m/s

M2=2.2 kg

V1=0 m/s(Assuming that the basketball is at rest)

Let's use again the inelastic collision formula to solve for their final velocity after they stick together:

M1V1+M2V2=(M1+M2)V2

Substituting and solving for V2,we have:

(1.5)(1.8)+(2.2)(0)=(1.5+2.2)V2

2.7+0=(3.7)V2

2.7=(3.7)V2

V2≈0.73 m/s

Therefore,the volleyball and basketball has a velocity of 0.73 m/s after they collided and stick together.