"Mr. Thomas invested an amount of 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be 3508, what was the amount invested in Scheme B?"
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Answer :
Explanation: Let the sum invested in Scheme A be x and that in Scheme B be (13900 - x).
==>Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 3508
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 350828x - 22x = 350800 - (13900 x 22)
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 350828x - 22x = 350800 - (13900 x 22)6x = 45000
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 350828x - 22x = 350800 - (13900 x 22)6x = 45000x = 7500.
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 350828x - 22x = 350800 - (13900 x 22)6x = 45000x = 7500.So, sum invested in Scheme B = (13900 - 7500) = 6400."
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 350828x - 22x = 350800 - (13900 x 22)6x = 45000x = 7500.So, sum invested in Scheme B = (13900 - 7500) = 6400."