The neutralization reaction between hydrochloric acid (HCI) and calcium hydroxide [Ca(OH)2 ] produces calcium chloride (CaCl2) and water.
If 0.75 grams of Ca(OH)2 is used in the reaction, determine the following:
a. number of moles of HCl (MM = 36.46g/mol) needed to completely react with Ca(OH)2. The molar mass of Ca(OH)2 is 74.10g/mol
b. mass of CaCl2 (MM = 110.98g / mol) formed in the reaction.
Answers & Comments
Answer:
Here we have 0.75 grams of calcium hydroxide were given them all massive calcium, hydroxide, 8 casum chloride. We want to find how many moles of hydrochloric acid, we need to neutralize or react with this casium hydroxide and the mass of calcium chloride. And here is a reaction were given in order to this this direction and so to the reacts with our casmidroxide to make gas and chloride, and so the first step is finding out how many moles of calcium hydroxide we have. So we have 0.75 grams t a o, h, 2 and we'll convert the to moles, so were gonna divide by 74.10 grams per mole grams cancel and we're left with moles, and we have 0.0101 moles of calcium hydroxide. So i'm going to go ahead and put that here so next we need to find how many moles of ah, we need to neutralize this. Well, it's a 2 to 1 rate, so we need twice as much cl as we need calcium hydroxide. So we're times this by 2, it wont come up 0.0202, moles, h, clay, start 0, that and so now these are an equal equivalents, so they're both going to go to 0. So this…