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shivasinghmohan629 @shivasinghmohan629

August 2021 1 8 Report

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3) solve the following equations :-

$\large\boxed{\textsf{\textbf{\red{Question\:A}}}}$

$a)4 = 5(p - 2)$

$ans) \: 4 = 5(p - 2)|$

$\frac{4}{5} = p - 2$

$p - 2 = \frac{4}{5}$

$p = \frac{4}{5} + 2$

$p = \frac{4 + 2 \times 5}{10}$

$p = \frac{4 + 10}{5} = \frac{14}{5}$

$\large\boxed{\textsf{\textbf{\red{Question\:B}}}}$

$b) \: - 4 = 5(p - 2)$

$ans) \: - 4 = 5(p - 2)$

$\frac{ - 4}{5} = p - 2$

$p - 2 = \frac{ - 4}{5}$

$p = \frac{ - 4}{5 } + 2$

$p = \frac{ - 4 + 2 \times 5}{5}$

$p = \frac{ - 4 + 10}{5} = \frac{10 - 4}{5} = \frac{6}{5}$

$\large\boxed{\textsf{\textbf{\red{Question\:C}}}}$

$c)16 = 4 + 3(t + 2)$

$ans)16 = 4 + 3(t + 2)$

$4 + 3(t + 2) = 16$

$3(t + 2) = 16 - 4 = 12$

$t + 2 = \frac{12}{ 3} = 4$

$t = 4 - 2 = 2$

$\large\boxed{\textsf{\textbf{\red{Question\:D}}}}$

$d)4 + 5(p - 1) = 34$

$ans)4 + 5(p - 1) = 34$

$5(p - 1) = 34 - 4$

$5(p - 1) = 30$

$p - 1 = \frac{30}{5} = 6$

$p = 6 + 1 = 7$

$\large\boxed{\textsf{\textbf{\red{Question\:E}}}}$

$e)0 = 16 + 4(m - 6)$

$ans)0 = 16 + 4(m - 6)$

$16 + 4(m - 6) = 0$

$4(m - 6) = - 16$

$m - 6 = \frac{ - 16}{4} = - 4$

$m = - 4 + 6 = 6 - 4 = 2$

4) (a) construct 3 equation starting with x = 2

(1)--

$x = 2$

Adding 2 on both sides

$x + 2 = 2 + 2$

$x + 2 = 4$

(2)--

$x = 2$

subtracting 2 from both sides

$x - 2 = 2 - 2$

$x - 2 = 0$

(3)--

$x = 2$

multiplying 2 on both the sides

$2 \times x = 2 \times 2 \\ 2x = 4$

(b) construct 3 equation starting with x = -2

(1)--

$x = - 2$

Adding 2 on the both the sides

$x + 2 = - 2 + 2 \\ = x + 2 = 0$

(2)--

$x = - 2$

subtracting 2 from both the sides

$x - 2 = - 2 - 2 \\ x - 2 = - 4$

(3)--

$x = - 2$

multiplaying 2 on the both the sides

$2 \times x = 2 \times ( - 2) \\ 2x = - 4$

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