Answer:
f = 12
Step-by-step explanation:
For the table refer to the attachement.
Mode = 45
so, modal class = 40 - 60
We have,
L = 40
H = 20
f₁ = f
f₀ = 10
f₂ = 6
⇒ Mode = L + (f₁ - f₀)H / (2f₁ - f₀ - f₂)
⇒ 45 = 40 + (f - 10)20 / (2f - 10 - 6)
⇒ 5 = (f - 10)20 / (2f - 16)
⇒ 1/4 = (f - 10) / (2f - 16)
⇒ 2f - 16 = 4f - 40
⇒ 2f = 24
⇒ f = 12
The missing frequency is 12 cm.
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Verified answer
Answer:
f = 12
Step-by-step explanation:
For the table refer to the attachement.
Mode = 45
so, modal class = 40 - 60
We have,
L = 40
H = 20
f₁ = f
f₀ = 10
f₂ = 6
⇒ Mode = L + (f₁ - f₀)H / (2f₁ - f₀ - f₂)
⇒ 45 = 40 + (f - 10)20 / (2f - 10 - 6)
⇒ 5 = (f - 10)20 / (2f - 16)
⇒ 1/4 = (f - 10) / (2f - 16)
⇒ 2f - 16 = 4f - 40
⇒ 2f = 24
⇒ f = 12
The missing frequency is 12 cm.