Answer:

The molecular weight of NaOH is 40 g/mol.

The number of moles of NaOH

40 g/mol

5 g

=0.125 moles.

500 ml water corresponds to0.500 L.

The molarity of the solution =

0.500 L

0.125 moles

=0.25 M

Answer:

Mole fraction = 1 mol / 1 mol = 1

Explanation:

Given:

Mass of NaOH = 40g

Volume of solution = 500 ml

Density of solution = 1.5 g/ml

We can first calculate the number of moles of NaOH in the solution as:

Number of moles = Mass / Molar mass

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Number of moles = 40g / 40 g/mol = 1 mol

Now, we can calculate the molarity of the solution as:

Volume of solution = 500 ml = 500/1000 = 0.5 L

Molarity = 1 mol / 0.5 L = 2 M

Next, we can calculate the molality of the solution as:

Molality = Number of moles of solute / Mass of solvent (in kg)

Mass of solvent = 1.5 g/ml * 500 ml = 750 g = 0.75 kg

Molality = 1 mol / 0.75 kg = 1.33 m

Finally, we can calculate the mole fraction of NaOH in the solution as:

Mole fraction = Number of moles of NaOH / Total number of moles of all components Total number of moles of all components = 1 mol (since NaOH is the only solute)

Mole fraction = 1 mol / 1 mol = 1

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