Explanation:

molality =98930×9101000=10. 43mol/Kg.

Verified answer

Explanation:

93 % HH2SO4 w/v means 93 g of HH2SO4

is present in 100cc of solution.

Since volume is 1000ml, amount of H2SO4

is 930 g/litre. Also density is given 1.84g/ml

M= density x volume = 1.84 x 1000 = 1840 g

wt of solvent = 1840 - 930 = 910 g

∵ molality= moles of solute/kg of solvent

∴ molality = 930/98× 1000/910

=10.43mol/Kg