Step-by-step explanation:
Answer 1:
(i) In AACD,
S is mid-point of DA.
[ Given]
R is mid-point of DC
Hence, SR || AC and SR = AC ... (1)
[ Mid Point Theorem]
(ii) In AACD,
P is mid-point of AB
Q is mid-point of BC
Hence, PQ || AC and PQ = AC ... (2)
From (1) and (2), we have
PQ || SR
... (3) PQ || AC and SR || AC]
and PQ = SR
... (4) [SR = = AC and PQ = AC]
(iii) In PQRS,
PQ || SR and PQ = SR Hence, PQRS is a parallelogram.
[ From (3) and (4)]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Step-by-step explanation:
Answer 1:
(i) In AACD,
S is mid-point of DA.
[ Given]
R is mid-point of DC
[ Given]
Hence, SR || AC and SR = AC ... (1)
[ Mid Point Theorem]
(ii) In AACD,
P is mid-point of AB
[ Given]
Q is mid-point of BC
[ Given]
Hence, PQ || AC and PQ = AC ... (2)
[ Mid Point Theorem]
From (1) and (2), we have
PQ || SR
... (3) PQ || AC and SR || AC]
and PQ = SR
... (4) [SR = = AC and PQ = AC]
(iii) In PQRS,
PQ || SR and PQ = SR Hence, PQRS is a parallelogram.
[ From (3) and (4)]