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Quadratic Equation and Solving it's Roots

In the mathematics, quadratic equation is define as any equation containing one variable that was raised to degree of two in which the unknown variable is squared. It was written in the form of ax² + bc + c = 0, where a ≠ 0.

For the answer of the attached photo.

1. B

2. B (it is possible when equated to zero)

3. C

4. C

5. A

6. C

7. C

8. A

9. it was -1

10. B

11. C

12. C

13. C

14. D

15. D

Solution and Explanation

Number 1

The standard form of quadratic equation is ax² + bx + c = 0, where a ≠ 0.

Number 2

It was letter B, since it has a quadratic term of -5n².

Number 3

The quadratic term is ax², so it was 5w².

Number 4

The linear term is bx, it was raised in one degree, so it was -7t.

Number 5

The quadratic equation has two roots, for the equation 3x² + 7x + 10 = 0. Through solving the equation using quadratic formula, 1/2a(-b ± √(b²-4ac)), it doesn't have a real roots. It was imaginary roots.

Number 6

For having a roots of -4 and -5, it can be written as (x + 4)(x + 5), the posible quadratic equation is x² + 9x + 20 = 0,

Number 7.

Having a no real roots, is when the value of 4ac is greater than the value of b². It was 2s² - 4s + 4 = 0, where b² = 16, and 4ac = 32.

Number 9

It can be solve using factoring, x² - 3x - 4 = 0, it was (x-4)(x+1), so the other root is -1.

Number 10.

The sum of quadratic equation is equal to -b/a. It was -(-10)/5 = 2.

Number 12

It can be solve through extracting square root.

Number 13

To make perfect square, use (1/2(b))², so it was (1/2(6))².

For number 8, 11, 14 and 15, it was incomplete given. The photo was cut.

Tips in Solving Math problems

• Apply your knowledge in previous topics.
• Don't forget the units of the problem, convert the unit first if necessary before you jump in the solution.
• Identify what formula is needed
• Create mathematical equation, then solve
• Check the solution
• Practice and practice solving word problems

Read more!

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