Answer:
Solution:
We're going to use Arithmetic sequence by determining first the common difference,
since, at first she has gained Php.500, and 2nd Php1000, then common difference is 500 or d = 500
500, 1000, 1500, 2000,...we can also use the formula to find the 8th and 10th sales period of time or term
Solving for the 8th sales
= + (n - 1) d (Equation)
= 500 + (8- 1) 500
= 500 + 7(500)
= 500 + 3500
= 4000, therefore the 8th sales is Php.4000
For the 10th sales period of time, the what we did for first
= + (n - 1) d
= 500 + (10- 1) 500
= 500 + 9(500)
= 500 + 4500
= 5000
Hence, the 10th sales is Php5000.
That is,
500, 1000, 1500, 2000, 2500, 3000, 3500, 4000, 4500, 5000
Thank you!
I hope you have got an idea.
Step-by-step explanation:
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Answers & Comments
Answer:
Solution:
We're going to use Arithmetic sequence by determining first the common difference,
since, at first she has gained Php.500, and 2nd Php1000, then common difference is 500 or d = 500
500, 1000, 1500, 2000,...we can also use the formula to find the 8th and 10th sales period of time or term
Solving for the 8th sales
= 500 + 7(500)
= 500 + 3500
= 4000, therefore the 8th sales is Php.4000
For the 10th sales period of time, the what we did for first
= 500 + 9(500)
= 500 + 4500
= 5000
Hence, the 10th sales is Php5000.
That is,
500, 1000, 1500, 2000, 2500, 3000, 3500, 4000, 4500, 5000
Thank you!
I hope you have got an idea.
Step-by-step explanation: