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solution (A) 5 g of sugar in 20 g of water.
solution(B) 10 g of sugar in 50 g of water.
solution (A)
%by mass = of solute/mass of solvent x 100
solution (B)
%by mass = of solute/mass of solvent x 100
solution (A) 5 g of sugar in 20 g of water.
solution(B) 10 g of sugar in 50 g of water.
solution (A)
%by mass = of solute/mass of solvent x 100
solution (B)
%by mass = of solute/mass of solvent x 100
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Explanation:
%by mass = mass of solvent
mass of solute
= 20 g
5 g
= 4 g² · 100
=400 g²
%by mass = mass of solvent
mass of solute
= 50 g
10 g
= 5 g² · 100
= 500 g²