Mass of 2.4088 × 1024 number of oxygen atoms is 6.4 g 64 g 0.8 g 68 g. Created by ujjwal26200. Chemistry

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Mass of 2.4088 × 1024 number of oxygen atoms is 6.4 g 64 g 0.8 g 68 g...

Mass of 2.4088 × 10²⁴ atoms of oxygen ?

First of all, we need to calculate the total number of molecules of oxygen in that sample:

$\sf \therefore \: molecules = \dfrac{atoms}{atomicity}$

$\sf \implies\: molecules = \dfrac{2.4088 \times {10}^{24} }{2}$

$\sf \implies\: molecules = 1.2044 \times {10}^{24}$

Now, let's calculate the number of moles:

$\sf \therefore \: moles = \dfrac{molecules}{avagadro \: number}$

$\sf \implies\: moles = \dfrac{1.2088 \times {10}^{24} }{6.023 \times {10}^{23} }$

$\sf \implies\: moles = \dfrac{12.088 \times {10}^{23} }{6.023 \times {10}^{23} }$

$\sf \implies\: moles \approx \: 2$

Now, finally the mass of oxygen:

$\sf \therefore \: mass = mole \times molar \: mass$

$\sf \implies \: mass = 2 \times 32$

$\sf \implies \: mass = 64 \: grams$

So, mass of oxygen in the sample is 64 grams.