Mary and Rose bought to buy some chocolate and candies Mary paid php 198 for 6 bars of chocolates and 12 pcs. of candies. Rose bought the same kinds of chocolates and candies but only paid less than php 100.Suppose each piece of candy cost php 4.How many bars of chocolates and pcs. of candies could Rose have bought?
A.4 bars of chocolates and 2 pcs. of candies
B. 3 bars of chocolates and 8 pcs. of candies
C. 3 bars of chocolates and 6 pcs. of candies
D. 4 bars of chocolates and 4 pcs. of candies
A.4 bars of chocolates and 2 pcs. of candies
B. 3 bars of chocolates and 8 pcs. of candies
C. 3 bars of chocolates and 6 pcs. of candies
D. 4 bars of chocolates and 4 pcs. of candies
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Answer:
C. 3 bars of chocolates and 6 pcs. of candies
Given:
Mary paid php 198:
6 bars of chocolates
12 pcs of candies
Rose - less than php 100
Cost of candy php 4
Step-by-step explanation:
12 pcs of candies × Cost of candy php 4 = php 48
Mary paid php 198 - php 48 = 150
150 ÷ 6 bars of chocolates that mary also bought = php 25
bars of chocolates - php 25
Cost of candy - php 4
A.4 bars of chocolates and 2 pcs. of candies
4(25) + 2(4) = 108
B. 3 bars of chocolates and 8 pcs. of candies
3(25) + 8(4) = 107
C. 3 bars of chocolates and 6 pcs. of candies
3(25) + 6(4) = 99
D. 4 bars of chocolates and 4 pcs. of candies
4(25) + 4(4) = 116
C is the answer.
Answer:
C
Step-by-step explanation:
12pcs candy × 4pesos/candy = 48pesos
198pesos - 48pesos = 150 pesos
150pesos ÷ 6 choco bar = 25pesos/choco bar
4x + 25y < 100
4(6) + 25(3) < 100
24 + 75 < 100
98 < 100