main triangle and any parallelogram are on the same base and between the same parallels the area of triangle is half the area of the parallelogram any army here???
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Answer: YES I AM AN ARMY TOO I LOVE BTS SO MUCH I REALLY LOVE TAEKOOK AND NICE SEEING YOU ARMY SO CAN YOU SEND ME FRIEND REQUEST BECUASE I WANT TO BE YOUR FRIEND
Step-by-step explanation:
Answer:
For Parallelogram ABCD
Since DM ⊥ AB
Height is DM,
Base Is AB
Area ABCD = Base × Height
Area ABCD = AB × DM ----- ( 1 )
For △PAB
Since PN ⊥ AB
Height Is PN, Base is AB
Area△PAB = ½ Base × Height
Area△PAB = ½ AB × PN
Since Opposite Sides Of Parallelogram Are Parallel So, AB ∥ CD
Distance Between Parallel Lines Are Equal
PN = DM
Area△PAB = ½ AB × DM ----- ( 2 )
From ( 1 ) And ( 2 )
Area△PAB= ½ Area ABCD
hEnCe pROvEd.