please this is urgent......
The size position of the metal is 10 ^ 10 N / m2. Its poise ratio is 0.20. If the average distance between the atoms is 3Å then the intermolecular force will be constant .....
A) 5.4 N/m
B) 7.5 N/m
C) 75 N/m
D) 30 N/m
The size position of the metal is 10 ^ 10 N / m2. Its poise ratio is 0.20. If the average distance between the atoms is 3Å then the intermolecular force will be constant .....
A) 5.4 N/m
B) 7.5 N/m
C) 75 N/m
D) 30 N/m
Answers & Comments
Answer:
A) 5.4 N/m ❌
B) 7.5 N/m ❌
C) 75 N/m. ✔️
D) 30 N/m ❌
Answer:
5.4 N/m
Explanation:
y=3k(1-2•)
=1.8×10¹⁰(1-2ו)
Inter atomic force constant is
K=1.8×10¹⁰×3×10‐¹⁰
=5.4N/m