Answer:
Apparent Weight = True weight – Upthrust = 7.8–1 = 6.8 N.
Given,
Density of Iron = 7.8×10³ kg/m³
Volume of iron piece = 100cm³ = 10⁻⁴m³
Density of water = 10³ kg/m³
To find,
The weight of Iron
Solution,
Density of Iron (Di) = 7.8×10³ kg/m³
Volume of iron piece (V) = 100cm³ = 10⁻⁴m³
Density of water (Dw) = 10³ kg/m³
weight of Iron (Mi )= ?
We can simply solve this numerical problem by using the following process:-
As we Know that,
Mass= Density×Volume
Therefore,
Mi= Di×V
Mi= 7.8×10³ kg/m³×10⁻⁴ m³
Mi=7.8×10⁻⁷ Kg
Hence, the weight of Iron is 7.8×10⁻⁷ Kg
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Verified answer
Answer:
Apparent Weight = True weight – Upthrust = 7.8–1 = 6.8 N.
Given,
Density of Iron = 7.8×10³ kg/m³
Volume of iron piece = 100cm³ = 10⁻⁴m³
Density of water = 10³ kg/m³
To find,
The weight of Iron
Solution,
Density of Iron (Di) = 7.8×10³ kg/m³
Volume of iron piece (V) = 100cm³ = 10⁻⁴m³
Density of water (Dw) = 10³ kg/m³
weight of Iron (Mi )= ?
We can simply solve this numerical problem by using the following process:-
As we Know that,
Mass= Density×Volume
Therefore,
Mi= Di×V
Mi= 7.8×10³ kg/m³×10⁻⁴ m³
Mi=7.8×10⁻⁷ Kg
Hence, the weight of Iron is 7.8×10⁻⁷ Kg