The volume decreases by approximately 0.04 m³
Explanation:
Considering that there is no change in pressure or the number of moles, we can use Boyle's law here, which states that
1 V Ρα
or
P₁V₁ = P₂V₂
Since we need to solve for the change in volume, we might as well find the new volume first.
V₂ P₁V₁ P2 =
Plugging in the values:
V₂ 50, 000, 000 Pa. 0.25 m³ 60,000,000 Pa = ≈ 0.21 m³
Now, we need to find the change in the volume, that is
AV = V₂ - V₁
We got:
Delta*V = 0.21m ^ 3 - 0.25m ^ 3
Delta*V = - 0.04m ^ 3
That means, that the volume has decreased by 0.04 m³.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
The volume decreases by approximately 0.04 m³
Explanation:
Considering that there is no change in pressure or the number of moles, we can use Boyle's law here, which states that
1 V Ρα
or
P₁V₁ = P₂V₂
Since we need to solve for the change in volume, we might as well find the new volume first.
V₂ P₁V₁ P2 =
Plugging in the values:
V₂ 50, 000, 000 Pa. 0.25 m³ 60,000,000 Pa = ≈ 0.21 m³
Now, we need to find the change in the volume, that is
AV = V₂ - V₁
We got:
Delta*V = 0.21m ^ 3 - 0.25m ^ 3
Delta*V = - 0.04m ^ 3
That means, that the volume has decreased by 0.04 m³.