The spring in the diagram is replaced with another spring that has a spring constant of 30 N/m. What is the stretch of this new spring when a 5-N block is attached?
To determine the stretch of the new spring when a 5-N block is attached, we can use Hooke's Law, which states that the force applied to a spring is proportional to its stretch or compression. The equation for Hooke's Law is:
F = kx
where F is the force applied, k is the spring constant, and x is the stretch or compression of the spring.
In this case, the original spring has a spring constant of 20 N/m, and the new spring has a spring constant of 30 N/m. Let's denote the stretch of the new spring by x.
We know that the force applied to the new spring is 5 N, so we can set up the following equation using Hooke's Law:
5 N = (30 N/m) * x
Solving for x, we get:
x = 5 N / (30 N/m) = 0.17 m
Therefore, the stretch of the new spring when a 5-N block is attached is 0.17 m (or 17 cm).
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Answer:
To determine the stretch of the new spring when a 5-N block is attached, we can use Hooke's Law, which states that the force applied to a spring is proportional to its stretch or compression. The equation for Hooke's Law is:
F = kx
where F is the force applied, k is the spring constant, and x is the stretch or compression of the spring.
In this case, the original spring has a spring constant of 20 N/m, and the new spring has a spring constant of 30 N/m. Let's denote the stretch of the new spring by x.
We know that the force applied to the new spring is 5 N, so we can set up the following equation using Hooke's Law:
5 N = (30 N/m) * x
Solving for x, we get:
x = 5 N / (30 N/m) = 0.17 m
Therefore, the stretch of the new spring when a 5-N block is attached is 0.17 m (or 17 cm).