Answer:
Given:
Radius of copper wire (r) = 3 cm = 0.03 m
Length of copper wire (L) = 1.0 m
Charge density (σ) = 12 µC/m² = 12 × 10^-6 C/m²
Formula:
Charge (Q) = σ × A
Area of circle (A) = πr²
Solution:
= 3.14 × (0.03 m)²
= 0.00282743339 m²
= (12 × 10^-6 C/m²) × (0.00282743339 m²)
= 0.000033928 C/m × m²
= 0.033928 C
Final Answer:
The total charge present in a 1.0-m long section of the copper wire is 0.033928 Coulombs.
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Answers & Comments
Answer:
Given:
Radius of copper wire (r) = 3 cm = 0.03 m
Length of copper wire (L) = 1.0 m
Charge density (σ) = 12 µC/m² = 12 × 10^-6 C/m²
Formula:
Charge (Q) = σ × A
Area of circle (A) = πr²
Solution:
Area of circle (A) = πr²
= 3.14 × (0.03 m)²
= 0.00282743339 m²
Charge (Q) = σ × A
= (12 × 10^-6 C/m²) × (0.00282743339 m²)
= 0.000033928 C/m × m²
= 0.033928 C
Final Answer:
The total charge present in a 1.0-m long section of the copper wire is 0.033928 Coulombs.