Answer:
Therefore, the freezing point of the trichothecin solution is 2.61 °C.
Explanation:
First, we need to calculate the molality of the trichothecin solution:
Molar mass of trichothecin (C19H2405) = 332.37 g/mol
Number of moles of trichothecin = 140 g / 332.37 g/mol = 0.421 mol
Mass of benzene = 0.746 kg = 746 g
Molality (m) = moles of solute / mass of solvent (in kg)
m = 0.421 mol / 0.746 kg = 0.564 mol/kg
Next, we can use the freezing point depression equation:
ΔTf = Kf × m
where ΔTf is the change in freezing point, Kf is the freezing point depression constant, and m is the molality of the solution.
Substituting the given values:
ΔTf = 5.12 °C/m × 0.564 mol/kg = 2.89 °C
Finally, we can calculate the freezing point of the solution:
Freezing point = Freezing point of pure solvent - ΔTf
Freezing point = 5.5 °C - 2.89 °C = 2.61 °C
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Answer:
Therefore, the freezing point of the trichothecin solution is 2.61 °C.
Explanation:
First, we need to calculate the molality of the trichothecin solution:
Molar mass of trichothecin (C19H2405) = 332.37 g/mol
Number of moles of trichothecin = 140 g / 332.37 g/mol = 0.421 mol
Mass of benzene = 0.746 kg = 746 g
Molality (m) = moles of solute / mass of solvent (in kg)
m = 0.421 mol / 0.746 kg = 0.564 mol/kg
Next, we can use the freezing point depression equation:
ΔTf = Kf × m
where ΔTf is the change in freezing point, Kf is the freezing point depression constant, and m is the molality of the solution.
Substituting the given values:
ΔTf = 5.12 °C/m × 0.564 mol/kg = 2.89 °C
Finally, we can calculate the freezing point of the solution:
Freezing point = Freezing point of pure solvent - ΔTf
Freezing point = 5.5 °C - 2.89 °C = 2.61 °C