Answer:
250dm = 25m height = [√{25² + {(72 - 65)/2}²] = √[625 + 12.25] = 25.24 m
So, Area of trapezium = (1/2) × (65 + 72) × (25.24) = 1728.94 sq.m
Therefore, cost of white washing Rs.5/m² = 1728.94/5 = Rs. 345.788
Step-by-step explanation:
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[tex]\huge\color{black}{ \colorbox{blue}{\colorbox{yellow} {answer\: \: }}}[/tex]
250 dm = 25 m
Length of parallel sides are 65 m and 72 m
Height = √25²+(72-65)²
= √625+7²
=√625+49
= √674
= 25.961 m
area of Trapezium = (1÷2) × sum of parallel side x distance between them
25.961
= (1-2) × (65+72) ×
= 1778.3285 m²
Therefore cost of painting the wall = area of wall x cost
1778.3285x155
||
275640.9175 Rs or Paise
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Verified answer
Answer:
250dm = 25m height = [√{25² + {(72 - 65)/2}²] = √[625 + 12.25] = 25.24 m
So, Area of trapezium = (1/2) × (65 + 72) × (25.24) = 1728.94 sq.m
Therefore, cost of white washing Rs.5/m² = 1728.94/5 = Rs. 345.788
Step-by-step explanation:
I hope it will help you
Drop some thx
And foll ow me plz
Thank you :)
[tex]\huge\color{black}{ \colorbox{blue}{\colorbox{yellow} {answer\: \: }}}[/tex]
250 dm = 25 m
Length of parallel sides are 65 m and 72 m
Height = √25²+(72-65)²
= √625+7²
=√625+49
= √674
= 25.961 m
area of Trapezium = (1÷2) × sum of parallel side x distance between them
25.961
= (1-2) × (65+72) ×
= 1778.3285 m²
Therefore cost of painting the wall = area of wall x cost
1778.3285x155
||
275640.9175 Rs or Paise