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A box of 12 dozen pen consist of a dozen defective pens . One pen is taken out at random. What is the probability that the pen taken out is -:
(i) defective?
(ii) non-defective?
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A box of 12 dozen pen consist of a dozen defective pens . One pen is taken out at random. What is the probability that the pen taken out is -:
(i) defective?
(ii) non-defective?
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Answers & Comments
Answer:
no. of pens = 12 dozen = 12 x 12 = 144.
no. of defective pens = 12.
therefore no. of non-defective pens = 144-12 = 132.
thus 132/144 = probability of not getting a defective pen.
therefore 132/144 = 11/12.
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Verified answer
Answer:
(i) To determine the probability of selecting a defective pen, we need to calculate the ratio of the number of defective pens to the total number of pens.
Given that there are 12 dozen pens, which is equal to 12 x 12 = 144 pens in total, and one dozen of them are defective, we know that there are 12 defective pens.
Therefore, the probability of selecting a defective pen can be calculated as follows:
Probability (defective pen) = Number of defective pens / Total number of pens
= 12 / 144
= 1 / 12
Hence, the probability of selecting a defective pen is 1/12.
(ii) Similarly, to calculate the probability of selecting a non-defective pen, we need to determine the ratio of the number of non-defective pens to the total number of pens.
Since we know that there are 12 dozen pens in total, and one dozen of them are defective, the remaining 11 dozen pens, or 11 x 12 = 132 pens, are non-defective.
Therefore, the probability of selecting a non-defective pen can be calculated as follows:
Probability (non-defective pen) = Number of non-defective pens / Total number of pens
= 132 / 144
= 11 / 12
Hence, the probability of selecting a non-defective pen is 11/12.
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