LT1. Find the product. Showyour solution.1. (c + d)^22.(c-d)^23.(c + d)(c-d)4.(c...

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September 2022 1 7 Report

LT1. Find the product. Show
your solution.
1. (c + d)^2
2.(c-d)^2
3.(c + d)(c-d)
4.(c + d)^3
5.(c-d)^3
6.(c+d+e) 12

Need na po now

Answers & Comments

Noether

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MULTIPLYING POLYNOMIALS

ANSWERS

1. (c + d)²

$\implies (c+d)(c+d) \\ \\ = c(c)+ c(d) + d(c) + d(d) \\ \\ = \boxed{ {c}^{2} + 2cd + {d}^{2} }$

2. (c - d)²

$\implies (c-d)(c-d) \\ \\ =c(c) + (c)(-d) + (-d)(c) + (-d)(-d) \\ \\ = \boxed{ {c}^{2} - 2dc + {d}^{2} }$

3. (c+d)(c-d)

$\implies =c(c)+(c)(-d)+d(c)+d(-d) \\ \\ = \boxed { {c}^{2} - {d} ^{2} }$

4. (c + d)(c + d)(c + d)

$\implies =(c+d)(c+d)(c+d) \\ \\ =({c}^{2}+2dc+{d}^{2})(c+d) \\ \\ ={c}^{2}(c)+2dc(c)+{d}^{2}(c)+{c}^{2}(d)+2dc(d)+d^{2}(d) \\ \\ ={c}^{3}+2d {c}^{2} + {d}^{2} c + d {c}^{2} + 2 {d}^{2} c - {d}^{3} \\ \\ = \boxed{ {c}^{3} + 3d {c}^{2} + 3 {d}^{2} c + {d}^{3} }$

5. (c - d)³

$\implies = (c - d)(c - d)(c - d)\\ \\ = ({c}^{2} - 2dc + d^{2})(c - d)\\ \\ = {c}^{2}(c) - 2dc(c) + d^{2}(c) + {c}^{2}(-d) - 2dc(-d) + d^{2}(-d) \\ \\ = {c}^{3} - 2d {c}^{2} + {d}^{2} c - d {c}^{2} + 2 {d}^{2} c - {d}^{3} \\ \\ = \boxed{ {c}^{3} - 3d {c}^{2} + 3 {d}^{2} c - {d}^{3} }$

6. (c + d + e)²

$\implies = (c + d + e) (c + d + e) \\ \\ = c(c) + c(d) + c(e) + d(c) + d(d) + d(e)+ e(c) + e(d) + e(e) \\ \\ = c^{2} + cd + ce + dc + d^{2} + de + ec + ed + e^{2} \\ \\ = \boxed{c^{2} + d^{2} + e^{2} + 2dc + 2de + 2 ec}$

Noether Hindi po maintindihan ang given sa 6 eh. Ano po bang given dun?

hotdog1512 (c + b + e ) my arrow po na pataas and then 12 po

hotdog1512 (c+b+e)^12

Noether Sure po kayo na raised to 12? Malaki po masyado 'yun at mas mabuti kubg gagamitan ng pascal's triangle para mas mabilis. Masyado pong mahaba ang solusyon kung raised to 12 ang given.

hotdog1512 ay 2 po pla sorry po hehe

hotdog1512 (c+b+e)^2 yan po nagkamali po pla ako hehe

Noether Sige po, idagdag ko na lang

hotdog1512 Sge po thank you po,Pwede po bang pasagot din po ng recent question ko po☺️

Noether Okay na po yung 6. Good luck and study well!

hotdog1512 Thank you po❤️

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