llQuestionll
Form the pair of linear equations in the following statements :-
(i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.
(ii) 5 pencils and 7 pens together cost ₹50, whereas 7 pencils and 5 pens together cost ₹46. Find the cost of one pencil and that of one pen.
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Answers & Comments
Step-by-step explanation:
(i) Let the number of boys who took part in the quiz be x, then the number of girls who took part in the quiz is x+4.
The total number of students who took part in the quiz is 10.
So, x+(x+4) = 10
Simplifying, we get 2x+4=10
or 2x=6
or x=3
Therefore, the number of boys who took part in the quiz is 3 and the number of girls who took part in the quiz is 3+4=7.
Hence, the required pair of linear equations is:
x + y = 10 ...(1)
x - y = -4 ...(2)
(ii) Let the cost of one pencil be x and the cost of one pen be y.
According to the given statement, we have:
5x + 7y = 50 ...(1)
7x + 5y = 46 ...(2)
Hence, the required pair of linear equations is:
5x + 7y = 50 ...(1)
7x + 5y = 46 ...(2)
Verified answer
Answer:
(i) Total number of students who took part in the the quiz =10
Let, the number of boys who took part in the quiz =x
and, number of girls who took part in the quiz =y
According to question,
x+y=10 ...........(1)
y=x+4 ..........(2)
By putting value of x=10−y in equation(2), we get
y=10−y+4
or, 2y=14
So, y=
2
14
=7
and x=10−7=3
Therefore,
Number of boys who took part in the quiz =3
Number of girls who took part in the class =7
(ii) Let the cost of a pencil be x and cost of one pen be y.
⇒5x+7y=50.......(1)
⇒7x+5y=46.......(2)
Adding and subtracting (1) and (2)
⇒2x−2y=−4
⇒12x+12y=96
⇒x−y=−2.........(3)
⇒x+y=8...........(4)
Add (3) and (4)
⇒2x=6
⇒x=3
⇒3−y=−2
⇒y=5
cost of one pencil=Rs 3
cost of one pen=Rs 5
Step-by-step explanation:
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