Let's ApplySolve for the surface area of the following figures.h = 14 m$= 12 inr...

Questions

October 2022 1 0 Report

Let's Apply
Solve for the surface area of the following figures.
h = 14 m
$= 12 in
r= 15 mm
r=2 m
5.
1.
3.
= 28 m
Stani height
A
A
Side of a base
2.
pasagot please

Answers & Comments

chaser27

$\large \mathbb{SOLUTION:1}$

$\footnotesize \begin{aligned} \tt \: GIVEN: \\ \tt \: s = 12 \: in \\ \\ \tt Formula : \\ \tt \: Area = 6a {}^{2} \\ \\ \tt \: Solution : \\ \\ \tt \: Area = 6 x 12 {}^{2} \\ \tt \: = 6 x 144 \\ \boxed{\tt \: surface \: area = 864 \: in {}^{2} } \end{aligned}$

$\large \mathbb{SOLUTION:2}$

$\footnotesize \begin{aligned} \tt \: GIVEN: \\ \tt \: Radius = 4 cm \\ \tt \: Height = 22 cm \\ \\ \tt \: Formula : \\ \tt \: Surface \: Area = πr(r + \sqrt{ (r² + h {}^{2} ))} \\ \\ \tt \: Solution : \\ \tt \: Surface \: Area = πr(r + slant \: height)) \\ \tt \: = 3.1416 x 4 x (4 + 22.3607) \\ \tt \: = 3.1416 x 4 x 26.3607 \\ \boxed{\tt \: Surface \: Area = 331.2581 cm {}^{2} } \end{aligned}$

$\large \mathbb{SOLUTION:3}$

$\footnotesize \begin{aligned} \tt \: GIVEN: \\ \tt \: Radius = 2 m \\ \tt \: Height = 14 m \\ \\ \tt \: Formula : \\ \tt \: Surface Area = 2πr(h + r) \\ \\ \tt \: Solution : \\ \tt \: Surface \: Area = 2 x 3.1416 x 2 x (14+2) \\ \tt \: = 2 x 3.1416 x 2 x 16 \\ \boxed{\tt \: Surface Area = 201.0619 m {}^{2}} \end{aligned}$

$\large \mathbb{SOLUTION:4}$

$\footnotesize \begin{aligned} \tt \: GIVEN: \\ \tt \: Base = 8 m \\ \tt \: Height = 28 m \\ \\ \tt \:Formula : \\ \tt \: Total \: Surface \: Area = Base(Base + \sqrt{ (Base {}^{2} + 4h {}^{2} )) } \\ \\ \tt \: Solution : \\ \tt \: Total \: Surface \: Area = 8 x (8 + \sqrt{ (8) {}^{2} + 4(28) {}^{2} )} \\ \tt \: = 8 x (8 + \sqrt{ (8)2 + 4(784)) }\\ \tt \: = 8 x (8 + \sqrt{(64 + 3136))} \\ \tt \: = 8 x (8 + \sqrt{ (3200)) }\\ \tt \: = 8 x (8 +(56.5685)) \\ \tt \: = 8 x (64.5685) \\ \boxed{ \tt \: Total \: Surface \: Area = 516.548 m {}^{2}} \end{aligned}$

$\large \mathbb{SOLUTION:5}$

$\footnotesize \begin{aligned} \tt \: GIVEN: \\ \tt \: Radius = 15mm \\ \\ \tt \: Formula : \\ \tt \: Surface \: Area = 4πr {}^{2} \\ \\ \tt \: Solution : \\ \tt \:Surface \: Area = 4 x 3.1416 x 15 {}^{2} \\ \tt \: = 4 x 3.1416 x 225 \\ \boxed{ \tt \: Surface \: Area = 2827.4334 mm {}^{2} } \end{aligned}$