Step-by-step explanation:
integers such that xy = 20 - 3x + y . Find the value of x + y. {only answer if you know, i will not tolerate wrong answers or
To find the value of x + y, we need to solve the given equation: xy = 20 - 3x + y.
Rearranging the terms, we have:
xy + 3x - y = 20.
Now, let's try to factorize the left side of the equation:
x(y + 3) - (y + 3) = 20.
We can observe that (y + 3) is a common factor:
(y + 3)(x - 1) = 20.
Next, we need to find the factors of 20 that satisfy the equation. The factors of 20 are: 1, 2, 4, 5, 10, and 20.
Let's substitute these values into the equation and solve for (x - 1):
(y + 3)(1 - 1) = 20, no solution
(y + 3)(2 - 1) = 20, no solution
(y + 3)(4 - 1) = 20, no solution
(y + 3)(5 - 1) = 20, y = 1, x = 6
(y + 3)(10 - 1) = 20, no solution
(y + 3)(20 - 1) = 20, no solution
We found a solution where y = 1 and x = 6.
Therefore, the value of x + y is:
6 + 1 = 7.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Step-by-step explanation:
integers such that xy = 20 - 3x + y . Find the value of x + y. {only answer if you know, i will not tolerate wrong answers or
To find the value of x + y, we need to solve the given equation: xy = 20 - 3x + y.
Rearranging the terms, we have:
xy + 3x - y = 20.
Now, let's try to factorize the left side of the equation:
x(y + 3) - (y + 3) = 20.
We can observe that (y + 3) is a common factor:
(y + 3)(x - 1) = 20.
Next, we need to find the factors of 20 that satisfy the equation. The factors of 20 are: 1, 2, 4, 5, 10, and 20.
Let's substitute these values into the equation and solve for (x - 1):
(y + 3)(1 - 1) = 20, no solution
(y + 3)(2 - 1) = 20, no solution
(y + 3)(4 - 1) = 20, no solution
(y + 3)(5 - 1) = 20, y = 1, x = 6
(y + 3)(10 - 1) = 20, no solution
(y + 3)(20 - 1) = 20, no solution
We found a solution where y = 1 and x = 6.
Therefore, the value of x + y is:
6 + 1 = 7.