Answer:
If (x+1) is a factor of given polynomial say p(X) , then at x= -1, p(x) will become zero, otherwise it is not a factor of given polynomial.
Step-by-step explanation:
hope this is your answer
x+1=0
x=−1
Put the value of x=−1 in all equations.
(i) x³ +x² +x+1
= (-1)³+( -1)² +(-1) +1
= -1+1-1+1
=0
therefore (x+1) factor of the equation
ii)x ³ −x ²−(2+ √2 )x+ √2 =(−1)³ −(−1)² −(2+ √2 )(−1)+ √2
=−1−1+2−√2 +√2
please mark brainliest
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Answer:
If (x+1) is a factor of given polynomial say p(X) , then at x= -1, p(x) will become zero, otherwise it is not a factor of given polynomial.
Step-by-step explanation:
hope this is your answer
Answer:
x+1=0
x=−1
Put the value of x=−1 in all equations.
(i) x³ +x² +x+1
= (-1)³+( -1)² +(-1) +1
= -1+1-1+1
=0
therefore (x+1) factor of the equation
ii)x ³ −x ²−(2+ √2 )x+ √2 =(−1)³ −(−1)² −(2+ √2 )(−1)+ √2
=−1−1+2−√2 +√2
=0
therefore (x+1) factor of the equation
please mark brainliest